Q14 / 150 · MHT CET 2026 (18 April Shift 1) · Chemistry
Which from following is obtained by hydroboration - oxidation of propene?
- APropanal
- BPropanone
- Correct answerCPropan-1-ol
- DPropan-2-ol
Solution
Hydroboration-oxidation of an alkene results in the anti-Markovnikov addition of water across the double bond.
Propene ($CH_3-CH=CH_2$) reacts with diborane ($B_2H_6$) to form tripropylborane as an intermediate.
Subsequent oxidation with hydrogen peroxide ($H_2O_2$) in an alkaline medium yields propan-1-ol.
$CH_3-CH=CH_2 \xrightarrow[2. H_2O_2, OH^-]{1. B_2H_6} CH_3-CH_2-CH_2-OH$
Answer: Propan-1-ol
Propene ($CH_3-CH=CH_2$) reacts with diborane ($B_2H_6$) to form tripropylborane as an intermediate.
Subsequent oxidation with hydrogen peroxide ($H_2O_2$) in an alkaline medium yields propan-1-ol.
$CH_3-CH=CH_2 \xrightarrow[2. H_2O_2, OH^-]{1. B_2H_6} CH_3-CH_2-CH_2-OH$
Answer: Propan-1-ol
Hence, the correct answer is option: 'C'.