Q8 / 90 · JEE Main 2024 (08 Apr Shift 1) · Chemistry

Combustion of glucose \(\left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)\) produces \(\mathrm{CO}_2\) and water. The amount of oxygen (in g) required for the complete combustion of \(900 \mathrm{~g}\) of glucose is : [Molar mass of glucose in \(\mathrm{g} \mathrm{mol}^{-1}=180\) ]

  • A
    480
  • B
    800
  • Correct answer
    C
    960
  • D
    32

Solution

$\begin{aligned} & \mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_{6(\mathrm{~s})}+6 \mathrm{O}_{2(\mathrm{~g})} \longrightarrow 6 \mathrm{CO}_{2(\mathrm{~g})}+6 \mathrm{H}_2 \mathrm{O}_{(\theta)} \\ & \frac{900}{180} \\ & =5 \mathrm{~mol} \quad 30 \mathrm{~mol}\end{aligned}$ Mass of $\mathrm{O}_2$ required $=30 \times 32=960 \mathrm{gm}$

Hence, the correct answer is option: 'C'.

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