Q126 / 270 · NDA 2016 (Phase 2) · General Ability

Code:

Code:
- A$\begin{array}{llll}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D} \\ 2 & 4 & 1 & 3\end{array}$
- B$\begin{array}{cccc}\text {A} & \text {B} & \text {C} & \text {D} \\ 3 & 4 & 1 & 2\end{array}$
- Correct answerC$\begin{array}{llll}\mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{D} \\ 2 & 1 & 4 & 3\end{array}$
- D$\begin{array}{cccc}\text {A} & \text {B} & \text {C} & \text {D} \\ 3 & 1 & 4 & 2\end{array}$
Solution
The correct answer is option (C)
Hence, the correct answer is option: 'C'.