Q37 / 180 · KCET 2016 · Chemistry

\( \mathrm{CO} \) is a stronger ligand than \( \mathrm{Cl}^{-} \), because

  • A
    \( \mathrm{CO} \) is a neutral molecule.
  • Correct answer
    B
    CO has \( \pi \)-bonds.
  • C
    \( \mathrm{CO} \) is poisonous.
  • D
    \( \mathrm{CO} \) is more reactive.

Solution

\( \mathrm{CO} \) is a stronger ligand than \( \mathrm{Cl}^{-} \)because, \( \mathrm{CO} \) is a \( \mathrm{II} \) - acceptor ligand due to multiple bonds in \( \mathrm{CO} \) and vacant
antibonding orbital of \( \mathrm{C} \) atom in \( \mathrm{CO} \).

Hence, the correct answer is option: 'B'.

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