Q10 / 54 · JEE Advanced 2020 (Paper 1) · Chemistry

Choose the correct statement(s) among the following:

Correct answer
A
${[{FeCl}_{4}]}^{-}$ has tetrahedral geometry.
B
${[Co (en) {({NH}_{3})}_{2} {Cl}_{2}]}^{+}$ has $2$ geometrical isomers.
Correct answer
C
${[{FeCl}_{4}]}^{-}$ has higher spin-only magnetic moment than ${[Co (en) {({NH}_{3})}_{2} {Cl}_{2}]}^{+}$
D
The cobalt ion in ${[Co (en) {({NH}_{3})}_{2} {Cl}_{2}]}^{+}$ has ${sp}^{3} d^{2}$ hybridization.

Solution

$(A)$ ${[{FeCl}_{4}]}^{-}$

Oxidation number of Fe atom $= + 3$

$Fe \to 3 d^{6} 4 s^{2}$

${Fe}^{3 +} \to 3 d^{5}$

$∴$ ${[{FeCl}_{4}]}^{-}$ is having tetrahedral geometry

$(B)$ ${[Co (en) {({NH}_{3})}_{2}]}^{+}$ have three geometrical isomers.

$(C)$ ${[{FeCl}_{4}]}^{-}$ is ${sp}^{3}$ hybridized with 5 -unpaired electrons. While $[Co (en) {({NH}_{3})}_{2} {Cl}_{2}] +$ is $d^{2} {sp}^{3}$ hybridised with zero unpaired electrons.

$(D)$ ${[Co (en) {({NH}_{3})}_{2} {Cl}_{2}]}^{+}$ has $d^{2} {sp}^{3}$ hybridization.

Hence, the correct answer is options: 'A', 'C'.

Choose the correct statement(s) among the following:

Solution

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