Q5 / 54 · JEE Advanced 2016 (Paper 1) · Chemistry

Among $[N i {(C O)}_{4}], {[N i C l_{4}]}^{2 -}, [C o {(N H_{3})}_{4} C l_{2}] C l, N a_{3} [C o F_{6}], N a_{2} O_{2}$ and $C s O_{2}$ , the total number of paramagnetic compounds is

A
$2$
Correct answer
B
$3$
C
$4$
D
$5$

Solution

	Compound/Ion		Unpaired Electron	Magnetic nature of compound
1]	$[N i {(C O)}_{4}]$	${3d}^{10}, {sp}^{3}$	$0$	Diamagnetic
2]	$[C o {(N H_{3})}_{4} C l_{2}] C l$	$3 d^{6}, d^{2} {sp}^{3}$	$0$	Paramagnetic
3]	${[N i C l_{4}]}^{2 -}$	$3 d^{8}, {sp}^{3}$	$2$	Diamagnetic
4]	$N a_{3} [C o F_{6}]$	$3 d^{6}, {sp}^{3} d^{2}$	$4$	Paramagnetic
5]	$N a_{2} O_{2}$	$O_{2}^{2 -}$	$0$	Diamagnetic
6]	$C s O_{2}$	$O_{2}^{- 1}$	$1$	Paramagnetic

So, the total number of paramagnetic compounds is

3

.

Hence, the correct answer is option: 'B'.

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