Calculate the wavelength (in nanometer) associated with a proton moving at 1.0 × 10^3 ~ms^-1 (Mass of proton =1.67 × 10^-27 ~kg and h=6.63 × 10^-34 Js ):

Correct answer: (B) 0.40 ~nm. λ=h/mv=frac6.63 × 10^-341.67 × 10^-27 × 10^3 ≡ 0.40 ~nm

Q21 / 90 · JEE Main 2009 · Chemistry

Calculate the wavelength (in nanometer) associated with a proton moving at $1.0 \times 10^3 \mathrm{~ms}^{-1}$ (Mass of proton $=1.67 \times 10^{-27} \mathrm{~kg}$ and $\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}$ ):

$$ \lambda=\frac{\mathrm{h}}{\mathrm{mv}}=\frac{6.63 \times 10^{-34}}{1.67 \times 10^{-27} \times 10^3} \equiv 0.40 \mathrm{~nm} $$

Hence, the correct answer is option: 'B'.