Q15 / 196 · NTA Abhyas (NEET) 2020 · Chemistry · Chemical Kinetics

Calculate the amount of $_{53} I^{128} (t_{1 / 2} = 25 m i n)$ left after 75 minutes.

A
$1 / 4$
B
$1 / 6$
Correct answer
C
$1 / 8$
D
$1 / 9$

Solution

\frac{N}{N_{0}} = {(\frac{1}{2})}^{\frac{t}{t_{1/2}}}; \frac{N}{N_{0}} = {(\frac{1}{2})}^{\frac{75}{25}}

N = amount at time t

t = total time

N_{0} = initial amount

Hence, the correct answer is option: 'C'.

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