Q18 / 150 · MHT CET 2026 (15 April Shift 2) · Chemistry
Calculate pOH of 0.001M HCl solution.
- Correct answerA$11$
- B$10$
- C$12$
- D$3$
Solution
HCl is a strong acid and dissociates completely in aqueous solution.
$[H^+] = 0.001 \text{ M} = 10^{-3} \text{ M}$
$pH = -\log[H^+] = -\log(10^{-3}) = 3$
Using the relation $pH + pOH = 14$
$pOH = 14 - 3 = 11$
Answer: $11$
$[H^+] = 0.001 \text{ M} = 10^{-3} \text{ M}$
$pH = -\log[H^+] = -\log(10^{-3}) = 3$
Using the relation $pH + pOH = 14$
$pOH = 14 - 3 = 11$
Answer: $11$
Hence, the correct answer is option: 'A'.