Q2 / 150 · MHT CET 2026 (19 April Shift 1) · Chemistry
What is the pH of solution containing $5 \times 10^{-4}\ \text{M}\ \text{H}^+$ ion?
- A$4.699$
- Correct answerB$3.301$
- C$5.401$
- D$3.725$
Solution
The pH of a solution is given by the negative logarithm of the hydrogen ion concentration:
$\text{pH} = -\log[\text{H}^+]$
Given $[\text{H}^+] = 5 \times 10^{-4}\ \text{M}$
$\text{pH} = -\log(5 \times 10^{-4})$
$\text{pH} = -(\log 5 + \log 10^{-4})$
$\text{pH} = -(\log 5 - 4)$
$\text{pH} = 4 - \log 5$
Using the value $\log 5 \approx 0.699$:
$\text{pH} = 4 - 0.699 = 3.301$
Answer: $3.301$
$\text{pH} = -\log[\text{H}^+]$
Given $[\text{H}^+] = 5 \times 10^{-4}\ \text{M}$
$\text{pH} = -\log(5 \times 10^{-4})$
$\text{pH} = -(\log 5 + \log 10^{-4})$
$\text{pH} = -(\log 5 - 4)$
$\text{pH} = 4 - \log 5$
Using the value $\log 5 \approx 0.699$:
$\text{pH} = 4 - 0.699 = 3.301$
Answer: $3.301$
Hence, the correct answer is option: 'B'.