Q26 / 150 · MHT CET 2024 (03 May Shift 2) · Chemistry

Calculate pH of 0.002 M KOH solution.

  • A
    10.4
  • Correct answer
    B
    11.3
  • C
    12.4
  • D
    13.2

Solution

$\begin{aligned} & \mathrm{pOH}=-\log _{10}\left[\mathrm{OH}^{-}\right] \\ & \because \quad \mathrm{pOH}=-\log _{10}[0.002]=2.69 \\ & \because \quad \mathrm{pH}+\mathrm{pOH}=14 \\ & \mathrm{pH}=14-\mathrm{pOH}=14-2.69=11.3\end{aligned}$

Hence, the correct answer is option: 'B'.

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