Q6 / 160 · WBJEE 2010 · Chemistry

Calculate $\mathrm{K}_{\mathrm{C}}$ for the reversible process given below if $\mathrm{K}_{\mathrm{P}}=167$ and $\mathrm{T}=800^{\circ} \mathrm{C}$ $\mathrm{CaCO}_3(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_2(\mathrm{~g})$

  • A
    1.95
  • B
    1.85
  • Correct answer
    C
    1.89
  • D
    1.60

Solution

Hints: $K_p=K_C(R T)^{\Delta n}$ for $\mathrm{eq}^{\mathrm{n}} \quad \mathrm{CaCO}_3(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_2(\mathrm{~g}), \Delta \mathrm{n}=1$ $\mathrm{K}_{\mathrm{C}}=\frac{\mathrm{K}_{\mathrm{P}}}{(\mathrm{RT})^{\Delta \mathrm{n}}}=\frac{167}{(0.0821 \times 1073)^1}=1.89$

Hence, the correct answer is option: 'C'.

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