Q35 / 102 · NTA Abhyas (JEE Main) 2020 · Chemistry · Ionic Equilibrium

Calculate dissociation constant for an acid HA having [H+] equals to 0.1 M (Given: degree of dissociation of HA is 1% )

  • A
    10-8
  • B
    10-6
  • Correct answer
    C
    10-3
  • D
    10-7

Solution

ka=α2C1-α , α is very small ;
∴1-α≈1
Cα = 0.1
k a  = (Cα)α
=0.01×0.1= 10 −3

Hence, the correct answer is option: 'C'.

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