BeO reacts with HF in presence of ammonia to give A which on thermal decomposition produces B and ammonium fluoride. Oxidation state of Be in A is

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Correct answer: 2. BeO on reaction with HF in the presence of ammonia, NH4_2BeF_4 is formed which on heating forms BeF_2 along with ammonium fluoride. BeO+2NH_3+4HF→NH4_2BeF_4+H_2O Compound A, is NH4_2BeF_4 NH4_2BeF_4→heatBeF_2+2NH_4F Compound B is BeF_2 In NH4_2BeF_4 the oxidation state of Be is +2.

$BeO$ reacts with $HF$ in presence of ammonia to give $[A]$ which on thermal decomposition produces $[B]$ and ammonium fluoride. Oxidation state of $Be$ in $[A]$ is

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