As shown in figure, the tension in the horizontal cord is $30 \mathrm{N}.$ The weight $w$ and tension in the string $OA$ in newton are

• A

  $30\sqrt{3}, 30$
• Correct answer
  B

  $30\sqrt{3},60$
• C

  $60\sqrt{3}, 30$
• D

  None of the above

Solution

Horizontal and vertical components of tension are shown in the figure.



From the figure, $T\sin {30}^o=30$ .....(i)

$T\cos {30}^o=w$ .....(ii)

By solving Equations (i) and (ii), we get

$w=30\sqrt{3}\mathrm{ N}$

and $T=60 \mathrm{N}$

Hence, the correct answer is option: 'B'.