Q166 / 200 · MHT CET - Medical 2026 (21 April Shift 1) · Physics
$C_p$ and $C_v$ are the specific heats at constant pressure and constant volume respectively. It is observed that $C_p - C_v = a$ for hydrogen gas and $C_p - C_v = b$ for carbon dioxide gas. The correct relationship between ' a' and 'b' is ( atomic weight of hydrogen , carbon and oxygen are 1u, 12 u and 16 u respectively)
- A$a = b$
- Correct answerB$a = 22\ b$
- C$a = 44\ b$
- D$a = \dfrac{1}{14b}$
Solution
For a given gas, the molar heat capacities at constant pressure and constant volume are related by Mayer's relation:
$C_{P,m} - C_{V,m} = R$
The specific heat is defined as the heat capacity per unit mass. Therefore, the difference between the specific heats at constant pressure ($C_p$) and constant volume ($C_v$) is given by:
$C_p - C_v = \dfrac{R}{M}$
where $M$ is the molar mass of the gas.
For hydrogen gas ($H_2$), the molar mass is $M_{H_2} = 2 \times 1 = 2$ u. Thus:
$a = \dfrac{R}{2}$
For carbon dioxide gas ($CO_2$), the molar mass is $M_{CO_2} = 12 + 2 \times 16 = 44$ u. Thus:
$b = \dfrac{R}{44}$
Taking the ratio of $a$ to $b$:
$\dfrac{a}{b} = \dfrac{\dfrac{R}{2}}{\dfrac{R}{44}} = \dfrac{44}{2} = 22$
$\Rightarrow a = 22 b$
Answer: $a = 22\ b$
$C_{P,m} - C_{V,m} = R$
The specific heat is defined as the heat capacity per unit mass. Therefore, the difference between the specific heats at constant pressure ($C_p$) and constant volume ($C_v$) is given by:
$C_p - C_v = \dfrac{R}{M}$
where $M$ is the molar mass of the gas.
For hydrogen gas ($H_2$), the molar mass is $M_{H_2} = 2 \times 1 = 2$ u. Thus:
$a = \dfrac{R}{2}$
For carbon dioxide gas ($CO_2$), the molar mass is $M_{CO_2} = 12 + 2 \times 16 = 44$ u. Thus:
$b = \dfrac{R}{44}$
Taking the ratio of $a$ to $b$:
$\dfrac{a}{b} = \dfrac{\dfrac{R}{2}}{\dfrac{R}{44}} = \dfrac{44}{2} = 22$
$\Rightarrow a = 22 b$
Answer: $a = 22\ b$
Hence, the correct answer is option: 'B'.