Q18 / 90 · JEE Main 2018 (16 Apr Online) · Chemistry

An unknown chlorohydrocarbon has 3.55 % of chlorine. If each molecule of the hydrocarbon has one chlorine atom only; chlorine atoms present in 1 g of chlorohydrocarbon are :(Atomic wt. of Cl=35.5 u; Avogadro constant =6.023×1023 mol–1)

  • A
    6.023 ×109
  • B
    6.023 ×1023
  • C
    6.023 ×1021
  • Correct answer
    D
    6.023 ×1020

Solution

CxHyCl

% Cl=3.55

Weight of Cl=1 ×3.55100

nCl-=1 ×3.55100 ×35.5

No. of Cl-ion= 1 × 3.55100 ×35.5×6.023 ×1023= 6.023 ×1020

Hence, the correct answer is option: 'D'.

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