Q24 / 170 · Manipal (MET) 2020 · Chemistry
An organic compound $A$ contains $20 \% \mathrm{C}$, $46.66 \% \mathrm{~N}$ and $6.66 \% \mathrm{H}$. It gives $\mathrm{NH}_3$ gas on heating with $\mathrm{NaOH} . A$ can be
- A$\mathrm{CH}_3 \mathrm{CONH}_2$
- B$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CONH}_2$
- Correct answerC$\mathrm{NH}_2 \mathrm{CONH}_2$
- D$\mathrm{CH}_3 \mathrm{NHCONH}_2$
Solution
\(\begin{aligned}
& C=\frac{20}{12}=1.66=1 \\
& N=\frac{46.66}{14}=3.33=2 \\
& H=\frac{6.66}{1}=6.66=4 \\
& O=\frac{26.68}{16}=1.66=1
\end{aligned}\)
Empirical formula of compound \(\mathrm{CN}_2 \mathrm{H}_4 \mathrm{O}\)
Since, this organic compound contains carbon, hydrogen, nitrogen and oxygen and on heating with alkali liberates \(\mathrm{NH}_3\) the organic compound must be urea.
\(\mathrm{NH}_2 \mathrm{CONH}_2+2 \mathrm{NaOH} \rightarrow 2 \mathrm{NH}_3+\mathrm{Na}_2 \mathrm{CO}_3\)
Hence, the correct answer is option: 'C'.