An organic compound contains $60\%\mathrm{C}; 4.48\%\mathrm{H}$ and $35.5\% \mathrm{O}.$ Its empirical formula is

According to the question, The empirical formula is the simplest formula of the relative ratio of elements in a compound.An empirical formula represents the simplest whole-number ratio of various atoms present in a compound. The molecular formula shows the exact number of different types of atoms present in a molecule of a compound.

$\mathrm{nC}:\mathrm{nH}:\mathrm{nO}=\frac{60}{12}:\frac{4.48}{1}:\frac{35.5}{16}= 5:4.48:2.21=5:4:2$

So empirical formula of compound is ${\mathrm{C}}_5{\mathrm{H}}_4{\mathrm{O}}_2$