Q13 / 181 · NTA Abhyas (JEE Main) 2020 · Physics · Laws of Motion

An object of mass 10 kg is connected to the lower end of a massless string of length 4 m hanging from the ceiling. If a force F is applied horizontally at the mid-point of the string, the top half of the string makes an angle of 45° with the vertical, then the magnitude of F is

  • A
    75 N
  • B
    90 N
  • Correct answer
    C
    100 N
  • D
    70 N

Solution

Figure

T2=100
T2=F
F=100 N

Hence, the correct answer is option: 'C'.

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