Q65 / 90 · JEE Main 2021 (27 Jul Shift 2) · Physics

An object of mass 0.5 kg is executing simple harmonic motion. It amplitude is 5 cm and time period (T) is 0.2 s. What will be the potential energy of the object at an instant t=T4 s starting from mean position. Assume that the initial phase of the oscillation is zero.

  • Correct answer
    A
    0.62 J
  • B
    6.2×10-3 J
  • C
    1.2×103 J
  • D
    6.2×103 J

Solution

T=2πmk

0.2=2π0.5k

k=50π2

≈500

x=Asin(ωt+ϕ)

=5 cmsinωT4+0

=5 cmsinπ2

=5 cm

PE=12kx2

=12(500)51002

=0.6255

Hence, the correct answer is option: 'A'.

Relevant Questions