An electric kettle takes 4 ~A current at 220 ~V . How much time will it take to boil 1 ~kg of water from temperature 20^° C ? The temperature of boiling water is 100^° C .

Correct answer: (B) 6.3 ~min. Vit =m c Δ θ t=(1 × 4200 × 80)/(220 × 4)=381.8 ~s=6.36 ~min

Q114 / 199 · NEET 2008 (Mains) · Physics

An electric kettle takes $4 \mathrm{~A}$ current at $220 \mathrm{~V}$. How much time will it take to boil $1 \mathrm{~kg}$ of water from temperature $20^{\circ} \mathrm{C}$ ? The temperature of boiling water is $100^{\circ} \mathrm{C}$.

A
$4.2 \mathrm{~min}$
Correct answer
B
$6.3 \mathrm{~min}$
C
$8.4 \mathrm{~min}$
D
$12.6 \mathrm{~min}$

Solution

$$ \begin{aligned} & \text { Vit }=m c \Delta \theta \\ & t=\frac{1 \times 4200 \times 80}{220 \times 4}=381.8 \mathrm{~s}=6.36 \mathrm{~min} \end{aligned} $$

Hence, the correct answer is option: 'B'.

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