An athlete, initially at rest, takes 2 s to reach his maximum speed of 36 km h^(-1). The magnitude of his average acceleration (in m s^(-2)) is

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MARKS Content Team · Accepted Answer

Correct answer: 5. The final speed of the athlete, v=36 km h^(-1)=36×5/18=10 m s^(-1) initial speed, u=0 time taken t=2 s for average acceleration, a v=u+at a=(v-u)/t=(10-0)/2=5 m s^(-2)

An athlete, initially at rest, takes $2 s$ to reach his maximum speed of $36 km h^{- 1}$ . The magnitude of his average acceleration (in $m s^{-2}$ ) is

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More Motion In One Dimension Questions

An athlete, initially at rest, takes 2 s to reach his maximum speed of 36 km h-1. The magnitude of his average acceleration (in m s-2) is

Solution

More Motion In One Dimension Questions

An athlete, initially at rest, takes $2 s$ to reach his maximum speed of $36 km h^{- 1}$ . The magnitude of his average acceleration (in $m s^{-2}$ ) is