Q21 / 150 · MHT CET 2022 (06 Aug Shift 2) · Chemistry

An acid dissociated to $1.5 \%$ in its $0.1 \mathrm{M}$ solution. Calculate its dissociation constant.

  • A
    $1.2 \times 10^{-5}$
  • Correct answer
    B
    $2.25 \times 10^{-5}$
  • C
    $1.1 \times 10^{-5}$
  • D
    $1.5 \times 10^{-5}$

Solution

$\begin{aligned} & K_a=\alpha^2 C \\ & =\left(\frac{1.5}{100}\right)^2 \times 0.1 \\ & =2.25 \times 10^{-5}\end{aligned}$

Hence, the correct answer is option: 'B'.

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