Q192 / 200 · MHT CET - Medical 2026 (22 April Shift 1) · Physics
An a.c. source is connected to a capacitor 'C'. Due to increase in its operating frequency
- Acapacitive reactance increases.
- Bcapacitive reactance remains constant.
- Correct answerCpeak current increases.
- Dpeak current decreases.
Solution
The capacitive reactance is given by $X_C = \dfrac{1}{\omega C} = \dfrac{1}{2\pi f C}$.
As the operating frequency $f$ increases, the capacitive reactance $X_C$ decreases.
The peak current is given by $I_0 = \dfrac{V_0}{X_C} = V_0 (2\pi f C)$.
Since $f$ increases, the peak current $I_0$ increases.
Answer: peak current increases.
As the operating frequency $f$ increases, the capacitive reactance $X_C$ decreases.
The peak current is given by $I_0 = \dfrac{V_0}{X_C} = V_0 (2\pi f C)$.
Since $f$ increases, the peak current $I_0$ increases.
Answer: peak current increases.
Hence, the correct answer is option: 'C'.