Q5 / 150 · JEE Main 2006 · Chemistry

According to Bohr's theory, the angular momentum of an electron in $5^{\text {th }}$ orbit is

A
$25 \frac{\mathrm{h}}{\pi}$
B
$1.0 \frac{\mathrm{h}}{\pi}$
C
$10 \frac{\mathrm{h}}{\pi}$
Correct answer
D
$2.5 \frac{\mathrm{h}}{\pi}$

Solution

$\begin{aligned} \mathrm{mvr} & =\frac{\mathrm{nh}}{2 \pi} \\ & =\frac{5 \mathrm{~h}}{2 \pi}=2.5 \frac{\mathrm{h}}{\pi}\end{aligned}$

Hence, the correct answer is option: 'D'.

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