Q140 / 170 · Manipal (MET) 2021 · Physics

A wave travelling in a stretched string is described by the equation $y=A \sin (k x-\omega t)$. The maximum particle velocity is :

  • Correct answer
    A
    $A \omega$
  • B
    $\omega / k$
  • C
    $d \omega / d k$
  • D
    $x / t$ -

Solution

$\begin{gathered}y=A \sin (k x-\omega t) \\ \frac{d y}{d t}=A \cos (k x-\omega t) \times(\omega) \\ \left(\frac{d y}{d t}\right)_{\max }=A(1)(\omega)=A \omega\end{gathered}$

Hence, the correct answer is option: 'A'.

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