Q141 / 170 · Manipal (MET) 2021 · Physics
A stretched sonometer wire is in unison with a tuning fork. When length of wire is increase by $1 \%$, the number of beats heard per second is 5. Then the frequency of the fork is :
- A500 Hz
- Correct answerB505 Hz
- C255 Hz
- D250 Hz
Solution
Let frequency of tuning fork be $n_1$
$\frac{n_2}{n_1}=\frac{100}{101}$
As $n_1-n_2=5$
So, $n_1=505 \mathrm{~Hz}$
Hence, the correct answer is option: 'B'.