Q141 / 170 · Manipal (MET) 2021 · Physics

A stretched sonometer wire is in unison with a tuning fork. When length of wire is increase by $1 \%$, the number of beats heard per second is 5. Then the frequency of the fork is :

  • A
    500 Hz
  • Correct answer
    B
    505 Hz
  • C
    255 Hz
  • D
    250 Hz

Solution

Let frequency of tuning fork be $n_1$ $\frac{n_2}{n_1}=\frac{100}{101}$ As $n_1-n_2=5$ So, $n_1=505 \mathrm{~Hz}$

Hence, the correct answer is option: 'B'.

More Waves and Sound Questions