A voltmeter of resistance $998 \Omega$ is connected across a cell of emf 2 V and internal resistance $2 \Omega$. The potential difference, across the voltmeter is

• Correct answer
  A

  1.99 V
• B

  3.5 V
• C

  5 V
• D

  6 V

Solution

From Ohm's law $i=\frac{E}{R+r}=\frac{2}{998+2}=2 \times 10^{-3} \mathrm{~A}$
Potential difference across the voltmeter is $\begin{aligned} V & =i R=\left(2 \times 10^{-3}\right) \times 998 \\ & =1.996 \mathrm{~V} \end{aligned}$

Hence, the correct answer is option: 'A'.