A uniform solid sphere of radius R produces a gravitational acceleration of a_o on its surface. The distance of the point from the centre of the…

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A uniform solid sphere of radius R produces a gravitational acceleration of a_o on its surface. The distance of the point from the centre of the sphere where the gravitational acceleration becomes a_o4 is,

MARKS Content Team · Accepted Answer

Correct answer: (C) 2R. On the surface of the uniform solid sphere, gravitational field(also called gravitational acceleration) is given by, -GMR^2=a_0. Gravitational field at any height h is given by, a=a_01+hR^(-2)⇒a_04=a_01+hR^(-2)⇒1+hR^2=4⇒h=R Hence, distance from the centre will be, =R+R=2R

A uniform solid sphere of radius $R$ produces a gravitational acceleration of $a_{o}$ on its surface. The distance of the point from the centre of the sphere where the gravitational acceleration becomes $\frac{a_{o}}{4}$ is,

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Relevant Questions

A uniform solid sphere of radius R produces a gravitational acceleration of ao on its surface. The distance of the point from the centre of the sphere where the gravitational acceleration becomes ao4 is,

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Relevant Questions

A uniform solid sphere of radius $R$ produces a gravitational acceleration of $a_{o}$ on its surface. The distance of the point from the centre of the sphere where the gravitational acceleration becomes $\frac{a_{o}}{4}$ is,