Q88 / 90 · JEE Main 2021 (27 Jul Shift 1) · Physics

A transistor is connected in common emitter circuit configuration, the collector supply voltage is $10 V$ and the voltage drop across a resistor of $1000 Ω$ in the collector circuit is $0.6 V .$ If the current gain factor $(β)$ is $24,$ then the base current is ____ $μA$ . (Round off to the Nearest Integer)

Correct answer: 25

Solution

$β = \frac{I_{C}}{I_{B}} = 24; R_{C} = 1000$

$Δ V = 0.6$

$I_{C} = \frac{0.6}{1000}$

$I_{C} = 6 \times 10^{- 4}$
$I_{B} = \frac{I_{C}}{β} = \frac{6 \times 10^{- 4}}{24} = 25 μ A$

Hence, the correct answer is 25.