Q150 / 160 · TS EAMCET 2010 · Physics

A transistor having a $\beta$ equal to 80 has a change in base current of $250 \mu \mathrm{A}$, then the change in collector current is

  • A
    $20,000 \mathrm{~mA}$
  • B
    $200 \mathrm{~mA}$
  • C
    $2000 \mathrm{~mA}$
  • Correct answer
    D
    $20 \mathrm{~mA}$

Solution

$\beta=\left(\frac{\Delta i_C}{\Delta i_B}\right)$ $80=\frac{\Delta i_C}{250 \times 10^{-6}}$ $\Delta i_C=80 \times 250 \times 10^{-6}$ $\Delta i_C=20000 \times 10^{-6}$ $=20 \times 10^{-3}=20 \mathrm{~mA}$

Hence, the correct answer is option: 'D'.

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