Q112 / 199 · NEET 2008 (Mains) · Physics
A thin rod of length $L$ and mass $M$ is bent at its midpoint into two halves so that the angle between them is $90^{\circ}$. The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is
- A$\frac{\sqrt{2} M L^2}{24}$
- B$\frac{M L^2}{24}$
- Correct answerC$\frac{M L^2}{12}$
- D$\frac{M L^2}{6}$
Solution
Distribution of masses about axis of rotation remain unchanged whether it is straight or bend.
$$
I=\frac{M L^2}{12}
$$
Hence, the correct answer is option: 'C'.