Q112 / 199 · NEET 2008 (Mains) · Physics

A thin rod of length $L$ and mass $M$ is bent at its midpoint into two halves so that the angle between them is $90^{\circ}$. The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is

  • A
    $\frac{\sqrt{2} M L^2}{24}$
  • B
    $\frac{M L^2}{24}$
  • Correct answer
    C
    $\frac{M L^2}{12}$
  • D
    $\frac{M L^2}{6}$

Solution

Distribution of masses about axis of rotation remain unchanged whether it is straight or bend. $$ I=\frac{M L^2}{12} $$

Hence, the correct answer is option: 'C'.

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