A tall tank filled with water has an irregular shape as shown. The wall $\mathrm{CD}$ makes an angle of $45^{\circ}$ with the horizontal; the wall $\mathrm{AB}$ is normal to the base $\mathrm{BC}$. The lengths $\mathrm{AB}$ and $\mathrm{CD}$ are much smaller than the height h of water (figure not to scale).
Let $\mathrm{P}_{1}, \mathrm{P}_{2}$ and $\mathrm{P}_{3}$ be the pressures exerted by the water on the wall $\mathrm{AB}$, base $\mathrm{BC}$ and the wall $\mathrm{CD}$ respectively. Density of water is $\rho$ and $g$ is acceleration due to gravity. Then, approximately

• Correct answer
  A

  $P_{1}=P_{2}=P_{3}$
• B

  $P_{1}=0, P_{3}=\frac{1}{\sqrt{2}} P_{2}$
• C

  $P_{1}=P_{3}=\frac{1}{\sqrt{2}} P_{2}$
• D

  $P_{1}=P_{3}=0, P_{2}=h \rho g$

Hence, the correct answer is option: 'A'.