Q49 / 105 · NTA Abhyas (JEE Main) 2020 · Physics · Center of Mass Momentum and Collision

A system of two identical, uniform discs with identical circular cavities, is shown in the figure. Different relevant coordinates are given in the figure. The coordinates of the centre of mass of the system are

 Figure

  • A
    3R2, 5R4
  • Correct answer
    B
    19R6, 5R2
  • C
    R2, R4
  • D
    20R6, 5R2

Solution

Mass of the removed portion

=MπR2×πR22

=M4

xcm=M·0-M4×R+M×7R-M4×8RM-M4+M-M4

=19R6

ycm=M·0-M40+M5R-M45RM-M4+M-M4

=5R2

Hence, the correct answer is option: 'B'.

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