Q177 / 200 · Manipal (MET) 2010 · Physics

A string fixed at both ends oscillates in 5 segments, length 10 m and velocity of wave is $20 \mathrm{~m} / \mathrm{s}$. What is the frequency?

Correct answer
A
5 Hz
B
15 Hz
C
10 Hz
D
2 Hz

Solution

Frequency of vibration is given by $n=\frac{p}{2 l} \sqrt{\frac{T}{m}} \left(\text { where } v=\sqrt{\frac{T}{m}}\right)$ $\therefore n=\frac{p v}{2 l}=\frac{5 \times 20}{2 \times 10}=5 \mathrm{~Hz}$

Hence, the correct answer is option: 'A'.

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