Q80 / 90 · JEE Main 2023 (31 Jan Shift 2) · Physics

A stone of mass 1kg is tied to end of a massless string of length 1 m. If the breaking tension of the string is 400 N, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is:

  • Correct answer
    A
    20 m s-1
  • B
     40 m s-1
  • C
    400 m s-1
  • D
    10 m s-1

Solution

In horizontal circle, tension towards the centre of the circular path at any moment will provide the required centripetal force.

Therefore,

Tmax=mv2r⇒400=1×v21⇒v=20 m s-1

Hence, the correct answer is option: 'A'.

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