Q23 / 201 · NTA Abhyas (NEET) 2020 · Physics · Atomic Physics

A stationary hydrogen atom in the first excited state emits a photon. If the mass of the hydrogen atom is m and its ionization energy is E, then the recoil velocity acquired by the atom is [speed of light = c]

  • Correct answer
    A
    3E2m+c2-c
  • B
    3E4m+c2-c
  • C
    3E4mc
  • D
    Emc

Solution

mv=hλ, here v is recoil speed of H-atom and λ is the wavelength of the photon.

When the electron jumps down from the first excited state to the ground state the energy released is

∆E2→1=E1-122=3E4

3E4=12mv2+hcλ

3E4=12mv2+mvc

 m2v2+mcv-3E4=0

⇒v=3E2m+c2-c

Hence, the correct answer is option: 'A'.

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