Q131 / 150 · MHT CET 2007 · Physics
A standing wave having 3 nodes and 2 antinodes is formed between two atoms having a distance $1.21 Å$ Å between them. The wavelength of the standing wave is
- Correct answerA$1.21 Å$
- B$1.42 Å$
- C$6.05 Å$
- D$3.63 Å$
Solution
Key Idea The given standing wave has 2 segments.
The given standing wave is shown in the figure.

As length of one loop or segment is $\frac{\lambda}{2}$, so length of 2 segments is $2\left(\frac{\lambda}{2}\right)$. $\therefore \quad 2 \frac{\lambda}{2}=1.21 Å$ $\Rightarrow \quad \lambda=1.21 Å$

As length of one loop or segment is $\frac{\lambda}{2}$, so length of 2 segments is $2\left(\frac{\lambda}{2}\right)$. $\therefore \quad 2 \frac{\lambda}{2}=1.21 Å$ $\Rightarrow \quad \lambda=1.21 Å$
Hence, the correct answer is option: 'A'.