Q131 / 150 · MHT CET 2007 · Physics

A standing wave having 3 nodes and 2 antinodes is formed between two atoms having a distance $1.21 Å$ Å between them. The wavelength of the standing wave is

  • Correct answer
    A
    $1.21 Å$
  • B
    $1.42 Å$
  • C
    $6.05 Å$
  • D
    $3.63 Å$

Solution

Key Idea The given standing wave has 2 segments. The given standing wave is shown in the figure. Figure
As length of one loop or segment is $\frac{\lambda}{2}$, so length of 2 segments is $2\left(\frac{\lambda}{2}\right)$. $\therefore \quad 2 \frac{\lambda}{2}=1.21 Å$ $\Rightarrow \quad \lambda=1.21 Å$

Hence, the correct answer is option: 'A'.

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