Q102 / 150 · MHT CET 2025 (5 May Shift 2) · Physics

The electric flux through the surface Figure

  • A
    in figure (c) is the largest
  • B
    in figure (b) is same as figure (c) but is smaller than figure (d)
  • Correct answer
    C
    is the same for all the figures
  • D
    in figure (d) is the least

Solution

Comparing electric flux through surfaces enclosing charge +q: Gauss's Law states that the electric flux $\Phi_E$ through any closed surface depends only on the enclosed charge: $\Phi_E = Q_{\text{enclosed}} / \epsilon_0$.

Since all four surfaces enclose the same charge $+q$, the flux is identical for each: $\Phi_a = \Phi_b = \Phi_c = \Phi_d = q / \epsilon_0$.

The flux is independent of the surface shape or size, rendering options A, B, and D incorrect. The correct choice is C, affirming flux equality across all figures.

Hence, the correct answer is option: 'C'.

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