Q143 / 160 · WBJEE 2009 · Physics

A spring of force constant $\mathrm{k}$ is cut into two equal halves. The force constant of each half is

A
$\frac{\mathrm{k}}{\sqrt{2}}$
B
$\mathrm{k}$
C
$\frac{\mathrm{k}}{2}$
Correct answer
D
$2 \mathrm{k}$

Solution

As $\quad \mathrm{K} \ell=$ constant $K^{\prime}=2 K$

Hence, the correct answer is option: 'D'.

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