A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N , when the lift is stationary. If the lift moves downward with an acceleration of 5 ~m / s^2 , the reading of the spring balance will be

Correct answer: (A) 24 ~N. Mass =49/9.8=5 ~kg . When lift is moving downward, apparent weight =5(9.8-5)=5 × 4.8=24 ~N

Q154 / 225 · JEE Main 2003 · Physics

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 $\mathrm{N}$, when the lift is stationary. If the lift moves downward with an acceleration of $5 \mathrm{~m} / \mathrm{s}^2$, the reading of the spring balance will be

Mass $=\frac{49}{9.8}=5 \mathrm{~kg}$. When lift is moving downward, apparent weight $=5(9.8-5)=5 \times 4.8=24 \mathrm{~N}$

Hence, the correct answer is option: 'A'.