A sound wave of frequency 200 Hz is travelling in air. The speed of sound in the air is 340 m s^(-1). What is the phase difference at a given instant…

Question

A sound wave of frequency 200 Hz is travelling in air. The speed of sound in the air is 340 m s^(-1). What is the phase difference at a given instant between two points separated by a distance of 85 cm along the direction of propagation?

MARKS Content Team · Accepted Answer

Correct answer: (A) π. First find out the value of the wavelength of the given data, here frequency, f=200 Hz, and speed of the sound wave, v=340 m s^(-1), it means the wavelength, λ=v/f=340/200=1.7 m, it means the phase difference, ∆ϕ=(2π)/(λ)×∆x⇒∆ϕ=(2π)/1.7×0.85=π

A sound wave of frequency $200 Hz$ is travelling in air. The speed of sound in the air is $340 m s^{- 1} .$ What is the phase difference at a given instant between two points separated by a distance of $85 cm$ along the direction of propagation?

Solution

More Oscillations Questions

A sound wave of frequency 200 Hz is travelling in air. The speed of sound in the air is 340 m s-1. What is the phase difference at a given instant between two points separated by a distance of 85 cm along the direction of propagation?

Solution

More Oscillations Questions

A sound wave of frequency $200 Hz$ is travelling in air. The speed of sound in the air is $340 m s^{- 1} .$ What is the phase difference at a given instant between two points separated by a distance of $85 cm$ along the direction of propagation?