The force ( F in newton) acting on a particle of mass 90 g executing simple harmonic motion is given by $\mathrm{F}+0.04 \pi^2 y=0$, where $y$ is displacement of the particle in meter. If the amplitude of the particle is $\frac{6}{\pi} \mathrm{~m}$, then the maximum velocity of the particle is

• A

  $6 \mathrm{~ms}^{-1}$
• B

  $2 \mathrm{~ms}^{-1}$
• C

  $8 \mathrm{~ms}^{-1}$
• Correct answer
  D

  $4 \mathrm{~ms}^{-1}$

Hence, the correct answer is option: 'D'.