Q25 / 105 · NTA Abhyas (JEE Main) 2020 · Physics · Center of Mass Momentum and Collision

A smooth sphere is moving on a horizontal surface with a velocity vector 2i^+2j^ m s-1 immediately before it hits a vertical wall. The wall is parallel to the vector j ^  and the coefficient of restitution between the sphere and the wall is e=12. The velocity of the sphere, after it hits the wall, is

  • A
    i ^ - j ^
  • Correct answer
    B
    - i ^ + 2 j ^
  • C
    - i ^ - j ^
  • D
    2 i ^ - j ^

Solution

12=0-vx2

vx=-1

v→=-i^+2j^

Figure

Hence, the correct answer is option: 'B'.

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