Q85 / 90 · JEE Main 2023 (24 Jan Shift 2) · Physics

A single turn current loop in the shape of a right angle triangle with sides 5 cm, 12 cm, 13 cm is carrying a current of 2 A. The loop is in a uniform magnetic field of magnitude 0.75 T whose direction is parallel to the current in the 13 cm side of the loop. The magnitude of the magnetic force on the 5 cm side will be x130 N. The value of x is _______.

Correct answer: 9

Solution

Figure

Here, B=0.75 T

The magnitude of magnetic force on the 5 cm side is FAB=i×lABBsinθ           angle between AC & AB

=2×5100×0.75×1213

=9130 N

Hence, the value of x=9.

Hence, the correct answer is 9.

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