Q113 / 180 · COMEDK 2022 · Mathematics
A regular polygon of $n$ sides has 170 diagonals, then $n$ is equal to
- A-20
- B-17
- C24
- Correct answerD20
Solution
The number of diagonals in a polygon with $n$ sides is given by the formula $D = \dfrac{n(n-3)}{2}$.
Given that the number of diagonals is 170, we set up the equation:
$\dfrac{n(n-3)}{2} = 170$
$n(n-3) = 340$
$n^2 - 3n - 340 = 0$
To solve this quadratic equation, we find factors of -340 that sum to -3. These are -20 and 17.
$(n - 20)(n + 17) = 0$
This gives $n = 20$ or $n = -17$.
Since the number of sides $n$ must be a positive integer, we have $n = 20$.
Answer: 20
Given that the number of diagonals is 170, we set up the equation:
$\dfrac{n(n-3)}{2} = 170$
$n(n-3) = 340$
$n^2 - 3n - 340 = 0$
To solve this quadratic equation, we find factors of -340 that sum to -3. These are -20 and 17.
$(n - 20)(n + 17) = 0$
This gives $n = 20$ or $n = -17$.
Since the number of sides $n$ must be a positive integer, we have $n = 20$.
Answer: 20
Hence, the correct answer is option: 'D'.