Q118 / 180 · NEET 2016 (Phase 1) · Physics

A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of EMF's is :

  • A
    5 : 1
  • B
    5 : 4
  • C
    3 : 4
  • Correct answer
    D
    3 : 2

Solution

FigureFigure

as  E∝L


E 1 + E 2 E 1 − E 2 = λ50 λ10

E1+E2=5E1-5E2

6E2=4E1

32=E1E2

Hence, the correct answer is option: 'D'.

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