Q141 / 200 · NEET 2024 (Re-NEET) · Physics
The given circuit shows a uniform straight wire $A B$ of 40 cm length fixed at both ends. In order to get zero reading in the galvanometer $G$, the free end of $J$ is to be placed from $B$ at:


- A32 cm
- B8 cm
- C16 cm
- Correct answerD24 cm
Solution
$\frac{8}{x}=\frac{12}{40-x}$
$\frac{2}{x}=\frac{3}{40-x}$
$80-2 x=3 x$
$16=x$
from B
$=40-16=24 \mathrm{~cm}$


Hence, the correct answer is option: 'D'.