Q141 / 200 · NEET 2024 (Re-NEET) · Physics

The given circuit shows a uniform straight wire $A B$ of 40 cm length fixed at both ends. In order to get zero reading in the galvanometer $G$, the free end of $J$ is to be placed from $B$ at: Figure

  • A
    32 cm
  • B
    8 cm
  • C
    16 cm
  • Correct answer
    D
    24 cm

Solution

$\frac{8}{x}=\frac{12}{40-x}$ $\frac{2}{x}=\frac{3}{40-x}$ $80-2 x=3 x$ $16=x$ from B $=40-16=24 \mathrm{~cm}$ Figure

Hence, the correct answer is option: 'D'.

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