A particle of mass $m$ moves in the $X Y$ plane with a velocity $v$ along the straight line $\mathrm{AB}$. If the angular momentum of the particle with respect to origin $\mathrm{O}$ is $L_A$ when it is at A and $L_B$ when it is at B, then:

• Correct answer
  A

  $L_A=L_B$
• B

  the relationship between $L_A$ and $L_B$ depends upon the slope of the line $\mathrm{AB}$
• C

  $L_A < L_B$
• D

  $L_A>L_{B^*}$

Solution

Moment of Momentum is angular momentum. OP is the same whether the mass is at $\mathrm{A}$ or $\mathrm{B}$

Hence, the correct answer is option: 'A'.